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y^2-8y-128=0
a = 1; b = -8; c = -128;
Δ = b2-4ac
Δ = -82-4·1·(-128)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-24}{2*1}=\frac{-16}{2} =-8 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+24}{2*1}=\frac{32}{2} =16 $
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